Question

es urgente, por favor

Answer 1

${n}^{2} = {5}^{2} + {4}^{2} \\ {n}^{2} = 25 + 16 \\ {n}^{2} = 41 \\ n = \sqrt{41}$

$P = \sqrt{41} \sin( \alpha ) - 1 \\ P = \sqrt{41} \times \frac{5}{ \sqrt{41} } - 1 \\ P = 5 - 1 \\ P = 4$