Question

A )x2+2 x 3 + 2x 2 = 13x − 10

b) (7 − 2x) + (5 + 3x) = 0

c) 3(x 2 + 2) − 4(x 2 − 1) + (x 2 + x − 5) = 0

d) 3(x 2 − 1) − 2(x + 6 − x 2 ) = 0

Answer 1

Respuesta:

A

2+2x3+2x2=13x-10

2+6+4=13x-10

12=13x-10

-13= -10-12

-13=-22

22

13

B

(7-2x)+(5+3x)=0

7-2x+5+3x =0

12 + x = 0

x= -12

C

3(x2+2)-4 (x2-1)+(x2+x-5)= 0

3(2x+2)-4(2x-1)+(2×+×-5)=0

6×+6-8x+4+(×-5) =0

6x+6-8x+4+x-5=0

-x+5=0

-x=-5

x=5

D

3(x2-1)-2(x+6-x2)=0

3(2x-1)-2(x+6-2x)=0

6x-3-2(-x+6)=0

6x-3+2x-12=0

8x-15=0

8x=15

x=15

8