Question

determina la ecuacion de las rectas a (2,2) y b(-3.5,5)

Answer 1

[(X - X1)/(X2 - X1)] = [(Y - Y1)/(Y2 - Y1)]

Donde:  X1 = 2;  Y1 = 2; X2 = -3.5; Y2 = 5

[(X - 2)/(-3.5 - 2)] = [(Y - 2)/(5 - 2)]

[(X - 2)/(-5.5)] = [(Y - 2)/(3)]

(X - 2)/(-5.5)= (Y - 2)/(3)

3(X - 2) = -5.5(Y - 2)

3X - 6 = -5.5 Y + 11

3X - 17 = - 5.5Y;  Dividimos todo entre -5.5

-0.545X + 3.09 = Y

Y = 3.09 - 0.545X