Question

siendo senθ = 2tg16° θ es agudo calcule c = tgθ cosθ = ctg 53°

Answer 1

Explicación paso a paso:

senθ = 2tg16°

senθ = 2(7/24) = 7/12

cosθ = ctg 53°

cosθ = 3/4

Hallamos C :

C = tgθ

C = senθ/cosθ

C = (7/12)/(3/4)

C = 7/9