Question

(4x⁵-8x³+16ײ)÷(4x²)​

Answer 1

Respuesta:

$\left(4x^5-8x^3+16x^2\right)\div \left(4x^2\right)$

$\frac{4x^2\left(x^3-2x+4\right)}{4x^2}$

$\left(x^3-2x+4\right)=\left(x+2\right)\left(x^2-2x+2\right)$

$\frac{4x^2\left(x+2\right)\left(x^2-2x+2\right)}{4x^2}$

$\frac{x^2\left(x+2\right)\left(x^2-2x+2\right)}{x^2}$

$\boxed{\left(x+2\right)\left(x^2-2x+2\right)}$

Saludos...