Question

alguien que me ayude porfa

Answer 1

T=(k-d²+(4Π/√4F))/(4kx+2Π-d)
T(4kx +2Π-d)=k-d²+(4Π/√4F)
T(4kx +2Π-d)-k+d²=(4Π/√4F)
T(4kx +2Π-d)-k+d²=(4Π/2√F)
T(4kx +2Π-d)-k+d²=(2Π/√F)
aplicando inversa a ambos lados:
1/( T(4kx +2Π-d)-k+d²)=(√F/2Π)
2Π/( T(4kx +2Π-d)-k+d²)=√F
elevando al cuadrado:
4Π²/( T(4kx +2Π-d)-k+d²)²=F
F=4Π²/( T(4kx +2Π-d)-k+d²)²