Question

a: I =5000mA R =3 kΩ (halle voltaje )

B: v=24v. I=12000 mA (hallé resistencia )
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Answer 1

a: I =5000mA R =3 kΩ (halle voltaje )

5000mA equivalen a 5A y 3k 3000, entonces...

$v = i \times r \\ v = 5 \times 3000 = \\ v = 15000voltios$

B: v=24v. I=12000 mA (hallé resistencia )

1200mA equivale a 12A

$r = \frac{v}{i} \\ r = \frac{24}{12} = 2ohm$