Question

Ayuda a resolver por factorizacion por favor ....
n2-6-n
x3+4x=7x
x2+6x +8=0
5x2+10x4=0

Answer 1

$n^{2} -6-n$

$n^{2} -n-6$+2n = n
n                -3
n               +2

-3n+2n = -n

(n-3)(n+2)


$x^{3} +4x = 7x$

$x^{3} -3x = 0$

$x( x^{2} -3)= 0$

x=0       

$x^{2} -3 = 0$

$x^{2} = 3$

$\sqrt{x^{2} } = \sqrt{3}$

$x = \frac{+}{} \sqrt{3}$

CS = ( -$\sqrt{3}; 0;  \sqrt{3}$ )


$x^{2} +6x+8 = 0$
x               +4
x               +2

2x + 4x = 6x

(x+4)(x+2) = 0

x +4= 0      x+2 = 0
x = -4         x = -2

CS = (-4; -2)