Question

Me ayudan en esto por fa .
(x+1) + (x+2) + (x+3) + .............. + (x+n)=n²

Answer 1

(x+1) + (x+2) + (x+3) + .............. + (x+n)=n²
nx + 1+ 2 + 3 +.......+n = n^2
nx + n*(n+1)/2 = n^2
nx + (n^2+n)/2 = n^2
2nx + n^2 + n = 2n^2
2nx = n^2 - n
2x = n - 1
x = (n - 1)/2

Answer 2

∞Resolver.
$(x+1)+(x+2)+(x+3)+.........+(x+n)= n^{2}$
$nx+1+2+3+......+n= n^{2}$
$nx+n \frac{(n+1)}{2} = n^{2}$
Se va "nx" y tambien "n" .
$2x+(n+1)=2n$
$2x=n-1$
$x= \frac{n-1}{2}$ ← Rpta.