Question

A.--0,\:17+2\sqrt{3}\cdot \sqrt{3}+\frac{1}{3}\div 1,\:6
B.-\left\{\:\left[\:\left(-\pi ^3\right)^{ }\right]^8\right\}=1\left\{\:\left[\:\left(-\pi ^3\right)^{ }\right]^8\right\}=


ayudenmee

Answer 1

Explicación paso a paso:

concuerdo contigo amigo

Answer 2

Respuesta:

\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)

Explicación paso a paso:

\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)\left(-3,\:2546+15,\:248\right)\div \left(-3,\:45\right)