Question

resuelve la siguiente identidad trigonometrica sin 2x ×cosx= 6 sin ³x​

Answer 1

Explicación paso a paso:

$\sin(2x) \cos(x) = 6 \sin^{3} (x)$

$[2 \sin(x) \cos(x) ] \cos(x) = 6 \sin^{3} (x)$

$2 \sin(x) \cos^{2} (x) = 6 \sin^{3} (x)$

$2 \sin(x) [1 - \sin^{2} (x)] = 6 \sin^{3} (x)$

$2 \sin(x) - 2 \sin^{3} (x) = 6 \sin^{3} (x)$

$∴\sin(2x) \cos(x) ≠6 \sin^{3} (x)$