• Asignatura: Matemáticas
  • Autor: ferlaorden22008
  • hace 3 años

ayudaaaaaaaaaaaaaaaaa!!!!!​

Adjuntos:

Respuestas

Respuesta dada por: Anónimo
1

A)

\frac{3}{5}\left(\frac{2}{5}-\frac{5}{2}\right)\\\\\\\frac{3}{5}\left(-\frac{21}{10}\right)\\\\\\-\frac{3\cdot \:21}{5\cdot \:10}\\\\\\-\frac{63}{5\cdot \:10}\\\\\\-\frac{63}{50}

B)

\left(-\frac{1}{4}+\frac{3}{6}\right)\frac{4}{3}\\\\\\\left(-\frac{1}{4}+\frac{1}{2}\right)\frac{4}{3}\\\\\\\frac{1}{4}\cdot \frac{4}{3}\\\\\\\frac{1}{3}

C)

\left(-\frac{6}{5}-\frac{3}{2}\right)\div \frac{2}{9}\\\\\\-\frac{27}{10}\div \frac{2}{9}\\\\\\-\frac{27\cdot \:9}{10\cdot \:2}\\\\\\-\frac{243}{10\cdot \:2}\\\\\\-\frac{243}{20}

D)

\left(\frac{3}{2}-\frac{1}{4}\right)\frac{2}{3}\\\\\\\frac{5}{4}\cdot \frac{2}{3}\\\\\\\frac{5}{2\cdot \:2}\cdot \frac{2}{3}\\\\\\\frac{5}{2}\cdot \frac{1}{3}\\\\\\\frac{5\cdot \:1}{2\cdot \:3}\\\\\\\frac{5}{2\cdot \:3}\\\\\\=\frac{5}{6}

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