Question

se analizo un hidrocarburo que contiene un 80% de C y 20% de H determinar la formula empiricay molecular. la masa molecular de hidrocarburo es 90g/mol

Answer 1

C: 80 g/ 12 g/mol = 6.667 mol
H: 20g/ 1 = 20 g/mol = 20 mol

dividir

C: 6.667 mol / 6.667 mol = 1
H: 20 mol / 6.667 ml = 3

FE = CH3

Mm FE

C: 1 x 12 = 12 g/mol
H: 3 x 1 = 3 g/mol
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       Mm = 15 g/mol

n = 90 g/mol / 15 g/mol = 6

FM = (FE)n  =  (CH3)6 = C6H18