Question

un compuesto tiene la siguiente composicion centesimal ba=52.5% n=10,7% o=36.8% sabiendo su peso molecular es de 261 g/mol calcular la formula molecular

Answer 1

Mm Ba=  137.32 g/mol
         N= 14 g/mol
         O = 16 g/mol

Ba: 52.5 g/ 137.32 = 0.3823 mol
N = 10.7 g/ 14 g/mol = 0.7642 mol
O: 36.8 g/ 16 g/mol = 2.3 mol

dividir

Ba: 0.3823 mol / 0.3823 mol = 1
N: 0.7642 mol / 0.3823 mol = 2
O: 2.3 mol / 0.3823 mol = 6

FE = Ba1N2O6

Mm de la FE
Ba: 1 x 173.32  = 173.32 g/mol
N: 2 x 14 = 28 g/mol
O= 6 X 16 = 96 g/mol
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         Mm = 297.32 g/mol

n = 261 g/mol
     ```````````````
      297.32 g/mol

n = 1

FM = Ba(NO3)2