Question

12. Si: P(x) = x2 + x + 1 Hallar: M = P(m+1) – P(m-2) – 6m

Answer 1

Respuesta:

M = 0

Explicación paso a paso:

P(x) = $x^{2}$ + x + 1

Hallar: M = P(m+1) – P(m-2) – 6m

Para P(m+1) tomamos x = m + 1

P(m+1) = $(m+1)^{2} +(m+1)+1$

P(m+1) = $m^{2}+2m + 1 +m+1+1$

P(m+1) = $m^{2}+3m + 3$

Para P(m-2) tomamos x = m - 2

P(m-2) = $(m-2)^{2} +(m-2)+1$

P(m-2) = $m^{2}-4m + 4 +m-2+1$

P(m-2) = $m^{2}-3m + 3$

Hallar: M = P(m+1) – P(m-2) – 6m

M = $m^{2}+3m + 3$ - ($m^{2}-3m + 3$) - 6m

M = $m^{2}+3m + 3$ - $m^{2}+3m - 3$ - 6m

M = 6m + 0 - 6m

M = 0