Question

Doy corona :)

ax2+bx+c=a(x−x1)(x−x2)

Answer 1

Respuesta:

(−11)(−12)

a(x-1x^{1})({\color{#c92786}{x-1x^{2}}})a(x−1x1)(x−1x2)

(−11)(−12+)

(−11)(−12+{\color{#c92786}{a(x-1x^{1}(-1x^{2}+x)}}

a(x−1x1)(−1x2+x)

(−12+)−(−12+) ⋅1

(−12+)−(−12+)⋅1

ax(−1x2+x)−a(−1x2+x)⋅x1

−3+2−(−12+)⋅1−

3

+

2−(

−

1

2

+

)

⋅

1−ax3+ax2−a(−1x2+x)⋅x1−3+2+3−2