Question

A rectangle's length is 8 m longer than its width, and its area is 128 m². Which of the following equations would be suitable to find the dimensions of the rectangle?

Mathematics

Answer 1

Greetings from Brazil!

$2x \cdot 2(x + 8) = 128\\2x\cdot2x+16=128\\4x^2=128-6\\4x^2=122\\x^2=122/4\\x^2=30,5\\x= \sqrt{30,5}\\x\cong5,52~m$

I hope I helped you! =)