Question

Porfavor ayuda, doy 100 puntos :(

Answer 1

Respuesta:

APROVECHARE TU PREGUNTA... AQUI ESTA EL PROCEDIMIENTO DE LO QUE ME FALTO

Explicación paso a paso:

f)

$25+8A=3A+60\\\\25+8A-25=3A+60-25\\\\8A=3A+35\\\\5A=35\\\\A=7$

g)

$5\left(A-6\right)=30\\\\\frac{5\left(A-6\right)}{5}=\frac{30}{5}\\\\A-6=6\\\\A=12$

h)

$2\left(5A-9\right)=42\\\\\frac{2\left(5A-9\right)}{2}=\frac{42}{2}\\\\5A-9=21\\\\5A=30\\\\\frac{5A}{5}=\frac{30}{5}\\\\A=6$

i)

$4A-56=16-2A\\\\4A-56+56=16-2A+56\\\\4A=-2A+72\\\\6A=72\\\\\frac{6A}{6}=\frac{72}{6}\\\\A=12$

j)

$\frac{A}{7}=90-2A\\\\\frac{A}{7}\cdot \:7=90\cdot \:7-2A\cdot \:7\\\\A=630-14A\\\\A+14A=630-14A+14A\\\\15A=630\\\\\frac{15A}{15}=\frac{630}{15}\\\\A=42$

k)

$\frac{\left(5A-8\right)}{4}=3\\\\\frac{4\left(5A-8\right)}{4}=3\cdot \:4\\\\5A-8=12\\\\5A-8+8=12+8\\\\5A=20\\\\\frac{5A}{5}=\frac{20}{5}\\\\A=4$

l)

$6A+18=3A+72\\\\6A+18-18=3A+72-18\\\\6A=3A+54\\\\6A-3A=3A+54-3A\\\\3A=54\\\\\frac{3A}{3}=\frac{54}{3}\\\\A=18$

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Answer 2

Respuesta:

\begin{gathered}25+8A=3A+60\\\\25+8A-25=3A+60-25\\\\8A=3A+35\\\\5A=35\\\\A=7\end{gathered}25+8A=3A+6025+8A−25=3A+60−258A=3A+355A=35A=7

g)

\begin{gathered}5\left(A-6\right)=30\\\\\frac{5\left(A-6\right)}{5}=\frac{30}{5}\\\\A-6=6\\\\A=12\end{gathered}5(A−6)=3055(A−6)=530A−6=6A=12

h)

\begin{gathered}2\left(5A-9\right)=42\\\\\frac{2\left(5A-9\right)}{2}=\frac{42}{2}\\\\5A-9=21\\\\5A=30\\\\\frac{5A}{5}=\frac{30}{5}\\\\A=6\end{gathered}2(5A−9)=4222(5A−9)=2425A−9=215A=3055A=530A=6

i)

\begin{gathered}4A-56=16-2A\\\\4A-56+56=16-2A+56\\\\4A=-2A+72\\\\6A=72\\\\\frac{6A}{6}=\frac{72}{6}\\\\A=12\end{gathered}4A−56=16−2A4A−56+56=16−2A+564A=−2A+726A=7266A=672A=12

j)

\begin{gathered}\frac{A}{7}=90-2A\\\\\frac{A}{7}\cdot \:7=90\cdot \:7-2A\cdot \:7\\\\A=630-14A\\\\A+14A=630-14A+14A\\\\15A=630\\\\\frac{15A}{15}=\frac{630}{15}\\\\A=42\end{gathered}7A=90−2A7A⋅7=90⋅7−2A⋅7A=630−14AA+14A=630−14A+14A15A=6301515A=15630A=42

k)

\begin{gathered}\frac{\left(5A-8\right)}{4}=3\\\\\frac{4\left(5A-8\right)}{4}=3\cdot \:4\\\\5A-8=12\\\\5A-8+8=12+8\\\\5A=20\\\\\frac{5A}{5}=\frac{20}{5}\\\\A=4\end{gathered}4(5A−8)=344(5A−8)=3⋅45A−8=125A−8+8=12+85A=2055A=520A=4

l)

\begin{gathered}6A+18=3A+72\\\\6A+18-18=3A+72-18\\\\6A=3A+54\\\\6A-3A=3A+54-3A\\\\3A=54\\\\\frac{3A}{3}=\frac{54}{3}\\\\A=18\end{gathered}6A+18=3A+726A+18−18=3A+72−186A=3A+546A−3A=3A+54−3A3A=5433A=354A=18