Question

resuelve las siguientes operaciones:

4-[6+[7-3+(6-3)]+8(4-2)]=


10-{12+[8-4(4-5)+14-12÷2]+8-6]+120=

con procedimiento porfa :(
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Answer 1

¡Saludos del Brazil!

$a) ~4-[6+[7-3+(6-3)]+8(4-2)]=\\\\4-[6+[7-3+3]+8\cdot2]=\\\\4-[6+7+8\cdot2]=\\\\4-[13+16]\\\\4-29\\\\-25$

$b)~10-[[12+[8-4(4-5)+14-12\div 2]+8-6]]+120$

$10-[[12+[8-4\cdot (-1)+14-6]+2]]+120$

$10-[[12+[8+4+14-6]+2]]+120$

$10-[[12+20+2]]+120$

$10-34+120$

¡Espero haberte ayudado! =)

Answer 2

Explicación paso a paso:

4-[6+[7-3+(6-3)]+8(4-2)]=

4-[6+(7-3+3)+8(2)

4-[6+7+16]

4-(29)

4-29

-25

10-{12+[8-4(4-5)+14-12÷2]+8-6]+120=

10-{12+[8-4(-1)+14-12 ÷ 2] +8-6]+120

10-[12+(8+4+14-12÷2)+8-6]+120

10-[12+(8+4+14-6)+8-6]+120

10-(12+20+8-6)+120

10-(40-6)+120

10-34+120

-24+120

96