a) 5 - [7-2-(1-9) - 3 +12] + 4 -
b)-1-(-3 + 6 +1)-[4-(6 - 3 + 1) - 2] -
c) 6-(-9 + 7 – 1) - [3 - (-5+4 +6)-1] -
d) 28 - [21-(12 - 3) - 7]-
[-2+3. (2 - 5)+3]-[(3 - 5 + 2) - 2-(3 - 4)]-
1) 8- [6 - (-3 + 7) - 6]+4 =
Con las operaciones por favor
Respuestas
a)5−(7−2−(1−9)−3+12)+4
=−1−(3+1)−(4−(6−3+1)−2)
=−1−4−(4−(6−3+1)−2)
=−5−(4−(6−3+1)−2)
=−5−(4−(3+1)−2)
=−5−(4−4−2)
=−5−(0−2)
=−5−(−2)
=−3
b)−1−(−3+6+1)−(4−(6−3+1)−2)
=−1−(3+1)−(4−(6−3+1)−2)
=−1−4−(4−(6−3+1)−2)
=−5−(4−(6−3+1)−2)
=−5−(4−(3+1)−2)
=−5−(4−4−2)
=−5−(0−2)
=−5−(−2)
=−3
c)6−(−9+7−1)−(3−(−5+4+6)−1)
=6−(−2−1)−(3−(−5+4+6)−1)
=6−(−3)−(3−(−5+4+6)−1)
=9−(3−(−5+4+6)−1)
=9−(3−(−1+6)−1)
=9−(3−5−1)
=9−(−2−1)
=9−(−3)
=12
d)28−(21−(12−3)−7)
=28−(21−9−7)
=28−(12−7)
=28−5
=23
e)8−(6−(−3+7)−6)+4
=8−(6−4−6)+4
=8−(2−6)+4
=8−(−4)+4
=12+4
=16
f) [-2+3. (2 - 5)+3]-[(3 - 5 + 2) - 2-(3 - 4)]
= [-2+3.(-3)+3] - [(-2+2)-2-(-1)]
= [-2+(-9)+3] - [(0)-2-(-1)]
= [-11+3] - [-2-(-1)]
= [-8] - [-1]
= -7
si la d) era uno solo la respuesta sería así:
d) 28 - [21-(12 - 3) - 7]- [-2+3. (2 - 5)+3]-[(3 - 5 + 2) - 2-(3 - 4)]
=28-[21-(9)-7]-[-2+3.(-3)+3]-[(-2+2)-2-(-1)]
=28-[12-7]-[-2+(-9)+3]-[(0)-2-(-1)]
=28-[5]-[-11+3]-[-2-(-1)]
=23-[-8]-[-1]
=31-[-1]
=32