x+2y+z=1
x-y+z=1
2x+y+2z=2​

Respuestas

Respuesta dada por: JonathanAlvaradoGonz
1

Respuesta:

Explicación paso a paso:

1.

x+2y+z=1\\\\x+2y+z-\left(2y+z\right)=1-\left(2y+z\right)\\\\x=1-2y-z

2.

x-y+z=1\\\\x-y+z-\left(-y+z\right)=1-\left(-y+z\right)\\\\x=1+y-z

3.

2x+y+2z=2\\\\2x+y+2z-\left(y+2z\right)=2-\left(y+2z\right)\\\\2x=2-y-2z\\\\\frac{2x}{2}=\frac{2}{2}-\frac{y}{2}-\frac{2z}{2}\\\\x=\frac{2-y-2z}{2}

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