Question

si
$log_{n} 8 = 3$
y
$log_{5}(k) = - 1$
entonces
${k}^{n}$
es?​

Answer 1

Explicación paso a paso:

$log_{n}(8) = 3 \\ {n}^{3} = 8 \\ {n}^{3} = {2}^{3} \\ n = 2$

$log_{5}(k) = - 1 \\ {5}^{ - 1} = k \\ k = \frac{1}{5}$

Entonces:

${k}^{n} = { (\frac{1}{5}) }^{2} = \frac{1}{25}$