Question

log(2x-7)-log(x-1)=log5

Answer 1

log(2x - 7) - log(x-1) = log 5
Propiedades
log[(2x - 7)/(x-1)] = log 5
(2x - 7)/(x -1) = 5
2x - 7 = 5(x - 1)
2x - 7 = 5x - 5
2x - 5x = -5 + 7
-3x = 2 (-1)
3x = -2
x = -2/3