Question

resuelve y coloca el procedimiento

Answer 1

Respuesta:

$a)2x - (4x + 2) = 6 + (2x - 1) \\ 2x - 4x - 2 = 6 + 2x - 1 \\ - 2x - 2 = 5 + 2x \\ - 2 - 5 = 2x + 2x \\ - 7 = 4x \\ - \frac{7}{4} = x$

$b)x - (10x - 15) = - ( - 2x + 8) \\ x - 10x + 15 = 2x - 8 \\ - 9x + 15 = 2x - 8 \\ 15 + 8 = 2x + 9x \\ 23 = 11x \\ \frac{23}{11} = x$

$c) - 3x + (5x - 3) = - 7x + (3x - 2) \\ - 3x + 5x - 3 = - 7x + 3x - 2 \\ 2x - 3 = - 4x - 2 \\ 2x + 4x = - 2 + 3 \\ 6 x = 1 \\ x = \frac{1}{6}$

$d) - 3x + ( - 8x + 4) = 2(x - 1) + 9(6x - 2) \\ - 3x - 8x + 4 = 2x - 2 + 54x - 18 \\ - 11x + 4 = 56x - 20 \\ 4 + 20 = 56x + 11x \\ 24 = 67x \\ \frac{24}{67} = x$