Question

Ayuda!
Resuelva 10x^2−19ax+6a^2 = 0 para a ∈ R

Answer 1

Hola.

$x= \frac{19a+ \sqrt{ (19a)^{2}-4*10*(6 a^{2} ) } }{2*10}= \frac{19a+ \sqrt{ 361a^{2}-240a^{2} } }{2*10} = \frac{19a+ \sqrt{ 121a^{2} } }{2*10}= \frac{19a+ 11a }{2*10}= \frac{30a }{20}= \frac{3a}{2}$

$x= \frac{19a- 11a }{2*10}= \frac{8a }{20}= \frac{2a}{5}$

Las soluciones serian:
$x= \frac{3a}{2}$
$x= \frac{2a}{5}$

Saludos !