Question

4ax^3 - 12axy - x^2 + 3y

Answer 1

Respuesta:

Holis!!

$4ax^3-12axy-x^2+3y\\=x^2\left(4ax-1\right)+3y\left(-4ax+1\right)\\=\left(-1+4ax\right)x^2-3\left(-1+4ax\right)y\\=\left(-1+4ax\right)\left(x^2-3y\right)$

Explicación paso a paso:

Espero y te sirva

:3