Question

$\frac{5 }{6} x {}^{2} + \frac{1}{2} = \frac{17}{10}$
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Answer 1

¡Hola!

$\frac{5}{6} {x}^{2} + \frac{1}{2} = \frac{17}{10} \\ \\ \frac{5}{6} {x}^{2} = \frac{17}{10} - \frac{1}{2} \\ \\ \frac{5}{6} {x}^{2} = \frac{17 - 5}{10} \\ \\ \frac{5}{6} {x}^{2} = \frac{12}{10} \\ \\ 5 {x}^{2} = \frac{6 \times 6}{5} \\ \\ {x}^{2} = \frac{ \frac{36}{5} }{5} \\ \\ {x}^{2} = \frac{36}{5 \times 5} = \frac{36}{25} \\ \\ \sqrt{ {x}^{2} } = \pm \frac{ \sqrt{36} }{ \sqrt{25} } \\ \\ x_{1} = \frac{6}{5} \\ \\ x_{2} = - \frac{6}{5}$

Entonces los valores de x son:

$\big\{x_{1} = \frac{6}{5} \ , \ x_{2} = - \frac{6}{5} \big\}$

Espero que sirva y saludos.