Question

no sé si me puedan ayudar a resolver ese problema de algebra por fis​

Answer 1

4x - 9x = (4-9)x

-5x = - 5x

-3mn + 7mn - 2mn

mn( - 3 + 7 - 2)

mn (4)

4mn

$\frac{1}{2} {a}^{2} {b}^{3} - \frac{2}{3} {a}^{2} {b}^{3} + \frac{5}{6} {a}^{2} {b}^{3} =$

$\frac{3}{6} {a}^{2} {b}^{3} - \frac{4}{6} {a}^{2} {b}^{3} + \frac{5}{6} {a}^{2} {b}^{3} =$

$\frac{8}{6} {a}^{2} {b}^{3} = \frac{4}{3} {a}^{2} {b}^{3}$

....... Kd