Question

y ese loq quiero entender ​

Answer 1

Respuesta:

Explicación paso a paso:

a.

Secx = 2, 0 < x < π/2

Secx = 1/cosx

cosx = 1/2

cos(x) = 2cos^2(x/2) - 1

1/2 = 2(1/2)^2 - 1

1/2 + 1 = 2cos^2(x/2)

3/2 = 2cos^2(x/2)

3/4 = cos^2(x/2)

cos(x/2) = √3/2

b.

csca = 5/3 ,  hallar tag2a

csca = 1/sena

sena = 3/5

cosa = 4/5

taga = 3/4

tag2a = (2taga)/(1-tag^2a)

tag2a = 2(3/4)/1-(3/4)^2

tag2a = (3/2)/1-(9/16)

tag2a = (3/2)/(7/16)

tag2a = 21/32

c.

cosθ = 2/3

senθ = √5/3

sen(θ/2) = √(1-cosθ)/2

sen(θ/2) = √(1-2/3)/2

sen(θ/2) = √1/6

sen(θ/2) = 1/√6 =√6/6

d.

csca = 3/2

sena = 2/3

cosa = √5/3

sen2a = 2senacosa

sen2a = 2(2/3)(√5/3) = 4√5/9

cos2a = 2cos^2(a) - 1

cos2a = 2(√5/3)^2 - 1

cos2a = 2(5/9) - 1 = 10/9 - 1 = 1/9

tag2a = (2taga)/(1-tag^2a)

tag2a = 2(2/√5)/(1-(2/√5)^2

tag2a = (4/√5)/(1-4/5)

tag2a = (4/√5)/(1/5)

tag2a = 20/√5 = 4√5