Question

Hallar los ceros o raíces del siguiente polinomio: P(x)=
${x}^{3} - {x}^{2 } - 2x$
​

Answer 1

Respuesta:

$p(x) = {x}^{3} - {x}^{2} - 2x$

$0 = {x}^{3} - {x}^{2} - 2x \\ {x}^{3} - {x}^{2} - 2x = 0 \\ x( {x}^{2} - x - 2) = 0 \\ x( {x}^{2} + x - 2x - 2) = 0 \\ x(x(x + 1) - 2(x + 1)) = 0 \\ x(x + 1)(x - 2) = 0$

$x_{1} = 0 \\ x _{2} = x + 1 = 0 \\ x = - 1 \\ x_{3} = x - 2 = 0 \\ x = + 2$