Question

Resolver las siguientes ecuaciones.
a. 23 +3a = 2a+ 59
b. 2b – 4 = b + 9
c. 2 + 7y = 4 – 3y
d. 5b – 10 = 4b – 12
e. 2a: 3=10
f. 3x – 4 = 24 – x
g. 5x/2 + 2 = 20 + 2
h. 5x + 2 = x + 10
i. 2x + 7=1 + 3x
j. z + 12 = 17
k. y – 18 = 2y – 3
l. 3 – 8b – 2= – 5 – 2b

Answer 1

Respuesta:

a.

23 +3a = 2a+ 59

3a - 2a = 59 - 23

a = 36

b.

2b – 4 = b + 9

2b - b = 9 + 4

b = 13

c.

2 + 7y = 4 – 3y

7y + 3y = 4 - 2

10y = 2

y = 2/10

y = 1/5

 

d.

5b – 10 = 4b – 12

5b - 4b = -12 + 10

b = -2

e.

2a: 3=10

2a = 10 * 3

2a = 30

a = 30/2

a = 15

f.

3x – 4 = 24 – x

3x + x = 24 + 4

4x = 28

x = 28/4

x = 7

g.

5x/2 + 2 = 20 + 2

5x/2 = 20 + 2 - 2

5x/2 = 20

5x = 20 * 2

5x = 40

x = 40/5

x = 8

h.

5x + 2 = x + 10

5x - x = 10 - 2

4x = 8

x = 8/4

x = 2

i.

2x + 7=1 + 3x

2x - 3x = 1 - 7

-x = -6

x = 6

j.

z + 12 = 17

z = 17 - 12

z = 5

k.

y – 18 = 2y – 3

y - 2y = -3 + 18

-y = 15

y = -15

l.

3 – 8b – 2= – 5 – 2b

-8b + 2b = -5 - 3 + 2

-6b = -6

b = -6/-6

b = 1

Explicación paso a paso: