resuelve por el método de Sustitución y Reducción cada una de las siguientes ecuaciones.
![](https://es-static.z-dn.net/files/da5/cd5aa276eef8554df191ce710a330708.jpg)
Respuestas
a )
3x - 2y = 1
4x - y = 0 (-2)
3x - 2y = 1
-8x + 2y = 0
3x - 2y - 8x + 2y = 1
-5x = 1
x = -1/5 = -0.20
3(-1/5) - 2y = 1
-3/5 - 2y = 1
-2y = 1 + 3/5
-2y = 8/5
y = 8/5 / -2
y = -4/5 = -0.80
b)
4x + 9y = 1 (-7)
7x - 8y = -9 (4)
-28x - 63y = -7
28x - 32y = -36
- 28x + 28x - 63y - 32y = - 7 - 36
-95y = -43
y = 43/95 = 0.45
4x + 9y = 1
4x + 9(43/95) = 1
4x + 387/95 = 1
4x = 1 - 387/95
4x = -292/95
x = -292/95 / 4
x = -292/380 = -0.77
c)
x - 4y = -5 (-2)
3x - 8y = 1
-2x + 8y = 10
3x - 8y = 1
-2x + 3x + 8y - 8y = 10 + 1
x = 11
x - 4y = -5
(11) - 4y = -5
-4y = -5 - 11
-4y = -16
y = -16/-4
y = 4
d)
5x - 2y = 10
4x + 2y = 8
5x + 4x - 2y + 2y = 10 + 8
9x = 18
x = 18/9
x = 2
5x - 2y = 10
5(2) - 2y = 10
10 - 2y = 10
-2y = 10 - 10
-2y = 0
y = 0
Respuesta:
a )
3x - 2y = 1
4x - y = 0 (-2)
3x - 2y = 1
-8x + 2y = 0
3x - 2y - 8x + 2y = 1
-5x = 1
x = -1/5 = -0.20
3(-1/5) - 2y = 1
-3/5 - 2y = 1
-2y = 1 + 3/5
-2y = 8/5
y = 8/5 / -2
y = -4/5 = -0.80
b)
4x + 9y = 1 (-7)
7x - 8y = -9 (4)
-28x - 63y = -7
28x - 32y = -36
- 28x + 28x - 63y - 32y = - 7 - 36
-95y = -43
y = 43/95 = 0.45
4x + 9y = 1
4x + 9(43/95) = 1
4x + 387/95 = 1
4x = 1 - 387/95
4x = -292/95
x = -292/95 / 4
x = -292/380 = -0.77
c)
x - 4y = -5 (-2)
3x - 8y = 1
-2x + 8y = 10
3x - 8y = 1
-2x + 3x + 8y - 8y = 10 + 1
x = 11
x - 4y = -5
(11) - 4y = -5
-4y = -5 - 11
-4y = -16
y = -16/-4
y = 4
d)
5x - 2y = 10
4x + 2y = 8
5x + 4x - 2y + 2y = 10 + 8
9x = 18
x = 18/9
x = 2
5x - 2y = 10
5(2) - 2y = 10
10 - 2y = 10
-2y = 10 - 10
-2y = 0
y = 0