Question

resuelve esto es para hoy porfa
(2m)(4m²-6m+9)
(-x²)(2x²+3x-1)
(-2m)(3m²-2m+1)​

Answer 1

Respuesta:

$(2m)(4 {m}^{2} - 6m + 9) \\ = 8 {m}^{2 + 1} - 12 {m}^{1 + 1} + 18m \\ = 8 {m}^{3} - 12 {}^{2} + 18m$

$( - {x}^{2} )(2 {x}^{2} + 3x - 1) \\ = - 2 {x}^{2 + 2} - 3 {x}^{1 + 2} - 1 {x}^{0 + 2} \\ = - 2 {x}^{4} - 3 {x}^{3} - x {}^{2}$

$( - 2m)(3 {m}^{2} - 2m + 1) \\ = - 6 {m}^{1 + 2} + 4 {m}^{1 + 1} - 2m \\ = - 6 {m}^{3} + 4 {m}^{2} - 2m$

Answer 2

Respuesta:

espero haberte ayudado =c

Explicación paso a paso:

$\left(2m\right)\left(4m^2-6m+9\right)\\\\\\=\left(2m\right)\cdot \:4m^2+\left(2m\right)\left(-6m\right)+\left(2m\right)\cdot \:9\\\\\\Aplicar\:las\:reglas\:de\:los\:signos..OjO\\\\\\+\left(-a\right)=-a\\\\\\\\=4m^2\left(2m\right)-6m\left(2m\right)+9\left(2m\right)\\\\\\=8m^3-12m^2+18m$

EJERCICIO 2)

$\left(-x^2\right)\left(2x^2+3x-1\right)\\\\\\=\left(-x^2\right)\cdot \:2x^2+\left(-x^2\right)\cdot \:3x+\left(-x^2\right)\left(-1\right)\\\\\\Aplicar\:las\:reglas\:de\:los\:signos...vuelvo..a...repetir\\\\\\=2x^2\left(-x^2\right)+3x\left(-x^2\right)-1\cdot \left(-x^2\right)\\\\\\=-2x^4-3x^3+x^2$

EJERCICIO 3)

$\left(-2m\right)\left(3m^2-2m+1\right)\\\\\\=\left(-2m\right)\cdot \:3m^2+\left(-2m\right)\left(-2m\right)+\left(-2m\right)\cdot \:1\\\\\\=3m^2\left(-2m\right)-2m\left(-2m\right)+1\cdot \left(-2m\right)\\\\\\=-6m^3+4m^2-2m\\\\\\Atte...nosenadaoficial$

puede que te ayude esto

          https://brainly.lat/tarea/40017143

solo anotate las formulas y ya...saludos...