Respuestas
Respuesta dada por:
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17) 2amx - 4a = 5mx + m - 2ax
2amx + 2ax - 5mx = m + 4a
x ( 2am + 2a - 5m) = m + 4a
x = (m + 4a) / (2am + 2a - 5m)
18) y^2 - 5xy + 12y = 6y - 10x + 3
10x - 5xy = 6y -12y + 3 - y^2
5x ( 2 - y) = 3 - 6y - y^2
x = (3 - 6y - y^2) / 5(2 - y)
19) (3/4)cbx - (1/2)b = (1/2)bx - (1/8)cx + (1/4)cb
(3/4)cbx - (1/2)bx + (1/8)cx = (1/4)cb + (1/2)b
x (3/4 cb - 1/2 b + 1/8 c) = (1/4)cb + (1/2)b
x (6cb - 4b + c)/8 = (cb + 2b)/4
x (6cb - 4b + c) = 2b (c + 1)
x = 2b(c+ 1) / (6cb - 4b + c)
20) (2/5)nx - (n^2)/6 + x/10 = 7/15 - x/3 + nx/2
(2/5)nx + x/10 + x/3 - nx/2 = 7/15 + (n^2)/6
nx (4 - 5)/10 + x (3 + 10)/10 = 7/15 + (n^2)/6
-nx/10 + 13x/10 = 7/15 + (n^2)/6
x (13 - n)/10 = 7/15 + (n^2)/6
x = [10/(13 - n)] (7/15 + (n^2)/6)
2amx + 2ax - 5mx = m + 4a
x ( 2am + 2a - 5m) = m + 4a
x = (m + 4a) / (2am + 2a - 5m)
18) y^2 - 5xy + 12y = 6y - 10x + 3
10x - 5xy = 6y -12y + 3 - y^2
5x ( 2 - y) = 3 - 6y - y^2
x = (3 - 6y - y^2) / 5(2 - y)
19) (3/4)cbx - (1/2)b = (1/2)bx - (1/8)cx + (1/4)cb
(3/4)cbx - (1/2)bx + (1/8)cx = (1/4)cb + (1/2)b
x (3/4 cb - 1/2 b + 1/8 c) = (1/4)cb + (1/2)b
x (6cb - 4b + c)/8 = (cb + 2b)/4
x (6cb - 4b + c) = 2b (c + 1)
x = 2b(c+ 1) / (6cb - 4b + c)
20) (2/5)nx - (n^2)/6 + x/10 = 7/15 - x/3 + nx/2
(2/5)nx + x/10 + x/3 - nx/2 = 7/15 + (n^2)/6
nx (4 - 5)/10 + x (3 + 10)/10 = 7/15 + (n^2)/6
-nx/10 + 13x/10 = 7/15 + (n^2)/6
x (13 - n)/10 = 7/15 + (n^2)/6
x = [10/(13 - n)] (7/15 + (n^2)/6)
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