Question

completar la siguiente tabla

Answer 1

Respuesta:

SIGNO

$- 5.9 {a}^{2} {b}^{3} c = menos \:$

$- \frac{ \sqrt{3} }{3} {h}^{4} {k}^{2} = menos$

$abc = mas$

$\frac{x {y}^{2} }{4} = mas$

$- 8 {a}^{4} {c}^{2} {d}^{3} = menos$

COEFICIENTES

$- 5.9 {a}^{2} {b}^{ 3} c = 5.9$

$- \frac{ \sqrt{3} }{3} {h}^{4} {k}^{2} = \frac{ \sqrt{3} }{3}$

$abc = 1$

$\frac{x {y}^{2} }{4} = \frac{1}{4}$

$- 8 {a}^{4} {c}^{2} {d}^{3} = 8$

PARTE LITERAL

$- 5.9 {a}^{2} {b}^{ 3} c = {a}^{2} {b}^{3} c$

$- \frac{ \sqrt{3} }{3} {h}^{4} {k}^{2} = {h}^{4} {k}^{2}$

$abc = abc$

$\frac{x {y}^{2} }{4} = x {y}^{2}$

$- 8 {a}^{4} {c}^{2} {d}^{3} = {a}^{4} {c}^{2} {d}^{3}$

EXPONENTES

$- 5.9 {a}^{2} {b}^{ 3} c = 2 + 3 + 1 = 6$

$- \frac{ \sqrt{3} }{3} {h}^{4} {k}^{2} = 4 + 2 = 6$

$abc = 1 + 1 + 1 = 3$

$\frac{x {y}^{2} }{4} = 1 + 2 = 3$

$- 8 {a}^{4} {c}^{2} {d}^{3} = 4 + 2 + 3 = 7$