Question

1.- 3ײ-5×-4=0
2.- 4ײ-20×+25=0
3.- ײ+6×+10=0

Answer 1

Respuesta:

hola...

Explicación paso a paso:

1)

$3x^2-5x-4=0\\\\x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:3\left(-4\right)}}{2\cdot \:3}\\\\\\x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{73}}{2\cdot \:3}\\\\\\x_1=\frac{-\left(-5\right)+\sqrt{73}}{2\cdot \:3},\:x_2=\frac{-\left(-5\right)-\sqrt{73}}{2\cdot \:3}\\\\\\x=\frac{5+\sqrt{73}}{6},\:x=\frac{5-\sqrt{73}}{6}$

2)

$4x^2-20x+25=0\\\\x_{1,\:2}=\frac{-\left(-20\right)\pm \sqrt{\left(-20\right)^2-4\cdot \:4\cdot \:25}}{2\cdot \:4}\\\\x_{1,\:2}=\frac{-\left(-20\right)\pm \sqrt{0}}{2\cdot \:4}\\\\\\x=\frac{-\left(-20\right)}{2\cdot \:4}\\\\\\x=\frac{5}{2}$

3)

$x^2+6x+10=0\\\\\\x_{1,\:2}=\frac{-6\pm \sqrt{6^2-4\cdot \:1\cdot \:10}}{2\cdot \:1}\\\\\\x_{1,\:2}=\frac{-6\pm \:2}{2\cdot \:1}\\\\\\x_1=\frac{-6+2}{2\cdot \:1},\:x_2=\frac{-6-2}{2\cdot \:1}\\\\\\x_1=\frac{-6+2}{2\cdot \:1},\:x_2=\frac{-6-2}{2\cdot \:1}$

$atte... nosenadaoficial$