Question

(4a3 + 1)3 =
Ayudenme

Answer 1

Respuesta:

$64a^9+48a^6+12a^3+1$

Explicación paso a paso:

$\mathrm{Aplicar\:la\:formula\:del\:binomio\:al\:cubo}:\quad \left(a+b\right)^3=a^3+3a^2b+3ab^2+b^3\\\\a=4a^3,\:\:b=1\\\\\left(4a^3+1\right)^3\\\\\left(4a^3\right)^3+3\left(4a^3\right)^2\cdot \:1+3\cdot \:4a^3\cdot \:1^2+1^3\\\\\left(4a^3\right)^3+3\cdot \:1\cdot \left(4a^3\right)^2+3\cdot \:4\cdot \:1\cdot \:a^3+1\\\\64a^9+48a^6+12a^3+1$