Question

El residuo de la división de
2x⁵ + 7x⁴ - 50x³- 173x²– 22x + 60
entre x² - 2x - 15 es


ayuda​

Answer 1

Respuesta:

hola???

Explicación paso a paso:

$\frac{2x^5+7x^4-50x^3-173x^2-22x+60}{x^2-2x-15}\\\\=\frac{\left(2x-1\right)\frac{2x^5+7x^4-50x^3-173x^2-22x+60}{2x-1}}{x^2-2x-15}\\\\=\frac{\left(2x-1\right)\left(x^4+4x^3-23x^2-98x-60\right)}{x^2-2x-15}\\\\=\frac{\left(2x-1\right)\left(x+3\right)\frac{x^4+4x^3-23x^2-98x-60}{x+3}}{x^2-2x-15}\\\\=\frac{\left(2x-1\right)\left(x+3\right)\left(x^3+x^2-26x-20\right)}{x^2-2x-15}\\\\=\frac{\left(2x-1\right)\left(x+3\right)\left(x-5\right)\left(x^2+6x+4\right)}{x^2-2x-15}$

$=\frac{\left(2x-1\right)\left(x-5\right)\left(x^2+6x+4\right)}{x-5}\\\\=\left(2x-1\right)\left(x^2+6x+4\right)$

Gracias...