Question

(2x³- x²+3x+1)•(x²- 6x)​

Answer 1

Respuesta:

(2x^3−x^2+3x+1)(x^2−6x)

=(2x^3+−x^2+3x+1)(x^2+−6x)

=(2x^3)(x^2)+(2x^3)(−6x)+(−x^2)(x^2)+(−x2)(−6x)+(3x)(x^2)+(3x)(−6x)+(1)(x^2)+(1)(−6x)

=2x^5−12x4−x^4+6x^3+3x^3−18x^2+x^2−6x

=2x^5−13x^4+9x^3−17x^2−6x

Explicación paso a paso: