Question

la glucosa una masa molar de 180.10g/ mol y contiene 40.0% de c,67.2% de H y 53.3 de O. determina la formula del compuesto

Answer 1

C: 40.0 g / 12 g/mol = 3.333 mol
H: 6.72 g / 1 g/mol  = 6.72 mol
O= 53.3 g / 16 g/mol = 3.331 mol

dividir entre el menor de los resultados

C: 3.333 mol / 3.331 mol = 1
H: 6.72 mol / 3.331 mol = 2
O: 3.331 mol / 3.331 mol =1

FE: CH2O

MASA MOLECULAR DE LA FE
C: 1 X 12 = 12 g/mol
H: 2 x 1 = 2 g/mol
O: 1 x 16 = 16 g/mol
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         Mm = 30 g/mol

n= 180 g/mol / 30 g/mol = 6

FM = FEn

FM = (CH2O)6 = C6H12O6