Question

ENSERIO NECESITO AYUDA!!!
5 (2x+4)= 3(x+9)
8(2x+5)=2(3x+5)
9(2x-4)=6(x+12)
3 (y+1)=2(y+6=
5(y+2)=2(2y+2)
10(x+2)=6(x+4)
Con procedimiento y comprobacion por fa

Answer 1

1)

$5(2x + 4) = 3(x + 9) \\ 10x + 20 = 3x + 27 \\ 10x - 3x = 27 - 20 \\ 7x = 7 \\ x = 7 \div 7 \\ x = 1$

Verificación:

$5(2 \times 1 + 4) = 3(1 + 9) \\ 5(2 + 4) = 3(1 + 9) \\ 5 \times 6 = 3 \times 10 \\ 30 = 30$

2)

$8(2x + 5) = 2(3x + 5) \\ 16x + 40 = 6x + 10 \\ 16x - 6x = 10 - 40 \\ 10x = - 30 \\ x = - 30 \div 10 \\ x = - 3$

Verificación:

$8(2 \times ( - 3) + 5) = 2(3 \times ( - 3) + 5) \\ 8( - 6 + 5) = 2( - 9 + 5) \\ 8 \times ( - 1) = 2 \times ( - 4) \\ - 8 = - 8$

3)

$9(2x - 4) = 6(x + 12) \\ 18x - 36 = 6x + 72 \\ 18x - 6x = 72 + 36 \\ 12x = 108 \\ x = 108 \div 12 \\ x = 9$

Verificación:

$9(2 \times 9 - 4) = 6(9 + 12) \\ 9(18 - 4) = 6(9 + 12) \\ 9 \times 14 = 6 \times 21 \\ 126 = 126$

4)

$3(y + 1) = 2(y + 6) \\ 3y + 3 = 2y + 12 \\ 3y - 2y = 12 - 3 \\ y = 9$

Verificación:

$3(9 + 1) = 2(9 + 6) \\ 3 \times 10 = 2 \times 15 \\ 30 = 30$

5)

$5(y + 2) = 2(2y + 6) \\ 5y + 10 = 4y + 12 \\ 5y - 4y = 12 - 10 \\ y = 2$

Verificación:

$5(2 + 2) = 2(2 \times 2 + 6) \\ 5(2 + 2) = 2(4 + 6) \\ 5 \times 4 = 2 \times 10 \\ 20 = 20$

6)

$10(x + 2) = 6(x + 4) \\ 10x + 20 = 6x + 24 \\ 10x - 6x = 24 - 20 \\ 4x = 4 \\ x = 4 \div 4 \\ x = 1$

Verificación:

$10(1 + 2) = 6(1 + 4) \\ 10 \times 3 = 6 \times 5 \\ 30 = 30$