Question

valor numérico
1. Si f(x)= 3x 2 + 8, hallar f(4) – f(-1)
2. Si f(x) = 2x –1; g(x) = 3x +2;
halle: f(2) + g(5) – 1

Answer 1

1. f(4) = 3×2+8= 14

f(-1)= (-1)×2+8= -2+8= 6

• f(4)-f(-1)

14-6= 8

2. f(2) = 2×(2)-1 =3

g(5)= 3×(5) +2 = 17

• f(2)+g(5)-1
• (3+17) -1 = 20-1=19