Question

calcula la derivada de
y= (4x²-2x+1) (2x+1)​

Answer 1

Respuesta:

Y =  ( 4x^2-2x+1 ) (2x+1)

d/dx[ Y ] = d/dx [ ( 4x^2-2x+1 ) (2x+1) ]

Y ' = d/dx [  4x^2-2x+1 ]*(2x+1)+d/dx [ 2x+1 ]*(4x^2-2x+1)

Y' = d/dx( [4x^2]-d/dx[-2x]+d/dx[1])(2x+1)+d/dx([2x]+d/dx[1])(4x^2-2x+1)

Y' = 8x-2+0(2x+1)+2+0(4x^2-2x+1)

Y' = ((8x-2)(2x+1))+((2(4x^2-2x+1))

Y' = 16x^2+4x-2+8X^2-4X+2

Y' = (16+8)x^2+(4 - 4)x+( -2+2 )

Y' = 24x^2+0x+0

Y' = 24x^2

R// La derivada de Y = ( 4x^2-2x+1 ) (2x+1) es Y' = 24x^2

Explicación paso a paso: