Question

Resolver el siguiente ejercicio me ayudan xfa ​

Answer 1

Explicación paso a paso:

$\frac{2}{1} \times \frac{3}{3} = \frac{6}{3} = 2$

$n = 0.4 \: periodico \\ 10n = 4.4 \\ 10n - n = 4.4 - 0.4 = \\ 9n = 4 \\ n = \frac{4}{9}$

$0.64 = \frac{0.64}{1} \times \frac{100}{100} = \frac{64}{100} \\ \sqrt{ \frac{64}{100} } =$

$\frac{ \sqrt{64} }{ \sqrt{100} } = \frac{8}{10}$

$( - \frac{1}{3} ) {}^{2} = \frac{ - 1}{3} \times \frac{ - 1}{3} = \frac{1}{9}$

$\frac{(2 + \frac{1}{3}) {}^{2} }{0.4 \sqrt{0.64 - ( \frac{ - 1}{3} ) {}^{2} } } = \frac{( \frac{6}{3} + \frac{1}{3}) {}^{2} }{ \frac{4}{9} + \frac{8}{9} + - \frac{1}{9} }{} =$

$= \frac{( \frac{7}{3} ) {}^{2} }{ \frac{4}{9} \times \frac{8}{10} - \frac{1}{9} } = \frac{ \frac{49}{9} }{ \frac{32}{90} - \frac{10}{90} } = \frac{ \frac{ \frac{49}{90} }{22} }{90} = \frac{49}{90} \times \frac{90}{22} = \frac{4410}{198} = \frac{2205}{99} = \frac{245}{11}$