Question

Dados cos (a)= 5/13 y Sen (b) 5/3, halla sen (a+b) y cos (a+b)​

Answer 1

Explicación paso a paso:

sena = 12/13

Cosb = 4/5

Sen(a+b) = senacosb + senbcosa

Sen(a+b) = (12/13)(4/5) + (3/5)(5/13)

Sen(a+b) = 48/65 + 15/65

Sen(a+b) = 63/65

Cos(a+b) = cosacosb - senasenb

Cos(a+b) = (5/13)(4/5) - (12/13)(3/5)

Cos(a+b) = 20/65 - 36/65

Cos(a+b) = -16/65