Question

1. Resuelva los siguientes cuadrados de un binomio a) (x + 3)2 =
b) (5 + a)^2 =
c) (6x + y)^2 =
d) (9 + 4x)^2 =
2. Resuelva los siguientes cubos de un binomio
a) (m + 3)^3 =
b) (5 – x)^3 =
c) (6a + b)^3 =
d) (9 + 4m)^3 =
3. Resuelva utilizando factor común
a) 4x - 8y =
b) 6x - 12 =
c) 24a - 12ab =
d) 14m^2n + 7mn =
e) 6x^4 - 30x^3 + 2x^2 =
4. Resuelva utilizando factor común por agrupación de términos
a)c^2+cd+cy+dy
b)x^2-a^2+x-a^2x
c)6ab+3a+1+2b
d)xy-b^2+2b^2y-6cy
porfaaa ayudaa:(

Answer 1

Explicación paso a paso:

$1.a) {(x + 3)}^{2} = {x}^{2} + 6x + 9$

$b) {(5 + a)}^{2} = 25 + 10a + {a}^{2}$

$c) {(6x + y)}^{2} = 36x + 12xy + {y}^{2}$

$d) {(9 + 4x)}^{2} = 81 + 72x + 16 {x}^{2}$

$2.a) {(m + 3)}^{3} = {(m + 3)}^{2}(m + 3) = ({m }^{2} + 6m + 9)(m + 3) = {m}^{3} + 3 {m}^{2} + 6 {m}^{2} + 18m + 9m + 27 = {m}^{3} + 9 {m}^{2} + 27m + 27$

$b) {(5 - x)}^{3} = ( {5 - x)}^{2} (5 - x) = (25 - 10x + {x}^{2}) (5 - x) = 125 - 25x - 50x + 10 {x}^{2} + 5 {x}^{2} - {x}^{3} = - {x}^{3} + 15 {x}^{2} - 75x + 125$

$c) {(6a + b)}^{3} = ({6a + b)}^{2} (6a + b) = (36 {a}^{2} + 12ab + {b}^{2} )(6a + b) = 216 {a}^{3} + 36 {a}^{2}b + 72 {a}^{2}b + 12a {b}^{2} + 6a {b}^{2} + {b}^{3} = 216 {a}^{3} + {b}^{3} + 108 {a}^{2}b + 18a {b}^{2}$

$d) {(9 + 4m)}^{3} = {(9 + 4m)}^{2} (9 + 4m) =( 81 + 72m + 16 {m}^{2} )(9 + 4m) = 729 + 324m + 648m + 288 {m}^{2} + 144 {m}^{2} + 64 {m}^{3} = 64 {m}^{3} + 432 {m}^{2} + 972m + 729$

$3.a)4x - 8y = 4(x - 2y)$

$b)6x - 12 = 6(x - 2)$

$c)24a - 12ab = 12a(2 - b)$

$d)14 {m}^{2} n + 7mn = 7mn(2m + 1)$

$e)6 {x}^{4} - 30 {x}^{3} + 2 {x}^{2} = 2 {x}^{2} (3 {x}^{2} - 15x + 1)$

$4.a) {c}^{2} + cd + cy + dy = c(c + d) + y(c + d) = cy(c + d)$

$b) {x}^{2} - {a}^{2} + x - {a}^{2} x = x(x + 1) - {a}^{2} (x + 1) = - {a}^{2}x(x + 1)$

$c)6ab + 3a + 1 + 2b = 3a(2b + 1) + 1(2b + 1) = 3a(2b + 1)$

$d)xy - {b}^{2} + 2 {b}^{2} y - 6cy = y(x - 6c) + {b}^{2} (2y - 1)$

Answer 2

Respuesta:

esa pregúnta la estaba buscando me ayudaste