• Asignatura: Matemáticas
  • Autor: angelguillermodiegoo
  • hace 3 años

ayudaaaaaaaaaaaaa porfis​

Adjuntos:

Respuestas

Respuesta dada por: incognitaxd66
1

Respuesta:

\left[\begin{array}{ccc}(\frac{2}{3}-\frac{1}{2}:\frac{3}{4} ):(\frac{5}{2}-\frac{3}{4} )-(\frac{9}{2} +\frac{1}{5} )\end{array}\right]  }: (\frac{2}{3} -\frac{5}{2} )+\left[\begin{array}{ccc}(\frac{3}{4} -\frac{5}{6} ).\frac{4}{7}-\frac{25}{42}  \end{array}\right]

\left[\begin{array}{ccc}(\frac{2}{3}-\frac{2}{3}):(\frac{7}{4} )-(\frac{47}{10} )\end{array}\right]  }: (-\frac{11}{6}  )+\left[\begin{array}{ccc}(-\frac{1}{12}).\frac{4}{7}-\frac{25}{42}  \end{array}\right]

\left[\begin{array}{ccc}0:(\frac{7}{4} )-(\frac{47}{10} )\end{array}\right]  }: (-\frac{11}{6}  )+\left[\begin{array}{ccc}-\frac{1}{21}-\frac{25}{42}  \end{array}\right]

\left[\begin{array}{ccc}0-\frac{47}{10} \end{array}\right]  }: (-\frac{11}{6}  )+\left[\begin{array}{ccc}-\frac{9}{14}  \end{array}\right]

\left[\begin{array}{ccc}-\frac{47}{10} \end{array}\right]  }: (-\frac{11}{6}  )+\left[\begin{array}{ccc}-\frac{9}{14}  \end{array}\right]

\frac{141}{55} +(-\frac{67}{42})

\frac{1479}{770}

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