Question

porfa me ayudan plis plis

Answer 1

(1)

s= (4/8)^-4× (8/4)^2-(9/3)^6/[(3/9)^-2]^2+(4/12)^-1

s= (4/8)^-4 × (8/4)^2-(9/3)^6/(3/9)^-4+(4/12)^-1

s= (1/2)^-4×(8/4)^2-(9/3)^6/(3/9)^-4+(4/12)^-1

s= 16×(8/4)^2-(9/3)^6/(3/9)^-4+(4/12)^-1

s=16×2^2-(9/3)^6/(3/9)^-4+(4/12)^-1

s= 16×4-(9/3)^6/(3/9)^-4+(4/12)^-1

s=64-(9/3)^6/(3/9)^-4+ (4/12)^-1

s= 64-3^6/(3/9)^-4+(4/12)^-1

s=64-729/(3/9)^-4+(4/12)-1

s= 64-729/(1/3)^-4+(4/12)^-1

s= 64-729/81+(4/12)^-1

s=64-9+(4/12)^-1

s= 55+(4/12)^-1

s=55+(1/3)^-1

s=55+3

s=58

ya va la dos , edito esto y la pongo , es que tarde en escribirlo