Question

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Answer 1

Respuesta:

Explicación paso a paso:

(x+4)(x-4)= 16-8x+$x^{2}$

$(x+4)^{2} = x^{2} +8x+16$

$(x+4)(x-1) = x^{2} +3x-4$

$(x-4)(x+1) = x^{2} -3x-4$

$(4x+1)(4x-1)= 16x^{2} -1$

$(4x-1)^{2} =16x^{2} -8x+1$

$(4+x)(4-x)= -x^{2} +16= 16-x^{2}$

$(4-x)^{2} =x^{2} -8x+16= 16-8x+x^{2}$

$(4x-1)(4x-1)= 16x^{2}-8x -1$