Question

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Answer 1

AC=AB+BC

AD=58u

58u= AB+BC+CD

58u=14u+BC+CD

58u-14u= BC+ 3BC/8

$44 = bc + \frac{3bc}{8}$

$44= \frac{8bc + 3bc}{8}$

$44= \frac{11bc}{8}$

$\frac{8 \times 44}{11} = bc$

$32 = bc$

Si Ac=AB+BC

AC=14+32

AC= 46u